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Question: 2.2.05-005

5 Points

Licenses: A A1 A2 B

You are driving at 100 km/h on a road not inside a built-up area. In front of you a truck is travelling at 70 km/h. What is the minimum distance you must be from a crest in the road when commencing an overtaking manoeuvre?

Choose one or multiple correct answers
  • A. 800 m
  • B. 200 m
  • C. 400 m

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Correct answer

  • A. 800 m
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Comment

The rule of thumb for the overtaking path is calculated from the speeds, the overtaking time and the vehicle lengths. The formula is s = v1 / (v1−v2) * (l1+l2+sv+sh). V1/ (V1-V2)) times L. V1 =100 km/h, V2 = 70 km/h, L = 2 times 50 m safety distance plus the vehicle lengths. Truck 12.5 m plus car 4.5 m = 17 m. L = 117 m. 100 km/h divided by 30 km/h times 117 m = 389.9 m, that means 400 m overtaking path. In confusing areas this has to be doubled. You must be at least 800 meters from the crest of the road.

Overtaking

Chapter 2.2.05

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